Cecilia's Random Thoughts
Tuesday, September 22, 2015
Some geometry
Problem:
In the figure CB and CD are opposite rays, CE bisects angle DCF and CG bisects FCB
Solution:
Because we have CE bisect angle DCF, therefore angle DCE = angle ECF, and so
4
x
+
15
=
6
x
−
5
20
=
2
x
x
=
10
So angle DCE is
4
x
+
15
=
55
.
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