Solution:
The problem is not complete because we don't know where x tends to, anyway we can still simplify.
limx2−2x+32x2+5x−3=limx2−2x+3(2x−1)(x+3) The numerator do not factor, so the problem is interesting really when x→0.5 or x→−3, in both case it tends to infinity, otherwise just simply substitute the value.
No comments:
Post a Comment