Saturday, September 26, 2015

Sequence

Problem:



The value of $ \sqrt{ 6 + \sqrt { 6 + \sqrt { 6 + .... \infty }}} $ is

Solution:

3

1 comment:

  1. Simply solve x = sqrt(6 + x)
    x^2 - x - 6 = 0
    (x - 3)(x + 2) = 0
    Only x = 3 works, x = -2 would work if the square root always take negative value instead.

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