Some arithmetic

Problem:



Solution:

$\begin{eqnarray*} & & \frac{-6^2 \div 4 \cdot (-3)}{3[4-(1-5)]} \\ &=& \frac{-6^2 \div 4 \cdot (-3)}{3[4-(-4)]} \\ &=& \frac{-6^2 \div 4 \cdot (-3)}{3[4+4]} \\ &=& \frac{-6^2 \div 4 \cdot (-3)}{3[8]} \\ &=& \frac{-6^2 \div 4 \cdot (-3)}{24} \\ &=& \frac{-36 \div 4 \cdot (-3)}{24} \\ &=& \frac{-9 \cdot (-3)}{24} \\ &=& \frac{27}{24} \\ &=& \frac{9}{8} \\ &=& 1\frac{1}{8} \\ \end{eqnarray*}$