Monday, September 21, 2015

Functions

Problem:




Solution: 

Part a)


The pressure at 0 feet is 15 (pound/square inch)
The pressure at 1 feet is 15 + 0.434 (pound/square inch)
The pressure at k feet is 15 + 0.434k (pound/square inch)

The pressure at 4 feet is 15 + 0.434(4) =  16.736 (pound/square inch)
The pressure at 31 feet is 15 + 0.434(31) = 28.454 (pound/square inch)

So the difference in pressure is  28.454 - 16.736 = 11.718 (pound/square inch) [positive for increase]

Part b)

The pressure at 26 feet is 15 + 0.434(26) = 26.284 (pound/square inch) 
The pressure at 4 feet is 15 + 0.434(4) =  16.736 (pound/square inch)

So the difference in pressure is  16.736 -26.284 = -9.548 (pound/square inch) [negative for decrease]

Part c)

j(n) = 15 + 0.434n

Part d)

i) Function name: j
ii) Input: n
iii) Output: j(n)
iv) j(n) = 15 + 0.434n
v) j(n) = 15 + 0.434n


I am not sure about part (d) - question of this sort usually have a strong dependency on the convention used in your teaching material, and I do not have access to those, sorry in advance if they are not accurate.

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