Three numbers

Problem:



The first of three numbers exceeds twice the second number by 4. while the third number is twice the first nmber. If the sum of three numbers is 54. Find the numbers.

Solution:

Let the second number be $ x $.
The first number is $ 2x + 4 $
The third number is $ 2(2x + 4) $

The sum of these numbers is $ x + 2x + 4 + 2(2x + 4) = 7x + 12 = 54 $. Therefore $ x = 6 $

The first number is $ 2x + 4 = 16 $
The second number is $ x = 6 $
The third number is $ 2(2x + 4) = 32 $