
Solution:
1)
Electronegativity increase from left to right in the periodic table because of octet rule.
Electronegativity decreease from top to bottom in periodic table because of atomic size.
a) Silicon < Sulfur < Chlorine [rule 1 above]
b) Rubidium < Potassium < Sodium [rule 2 above]
2)
a) Ionic: Rb+ Cl-
b) Covalent: S = S
c) Polar Covalent N ≡ P (electron will be more close to N than P)
d) Covalent CF4
3)
Atomic radius increase from right to left (they share similar orbitals in the same row, but with increased number of protons the orbital size decreases)
Atomic radius increase from top to bottom due to adding more orbitals.
a) O2−<S2−<SE2−<TE2−, this is rule 2
They are isoelectronic with Ne, Ar, Kr, Xe respectively
b) I<Te<Ba<Cs, this is rule 1 and rule 2 combined.
They are isoelectronic with Xe, Xe, Rn, Rn respectively.
4) We need to break 2 H-S bond, 3 F-F bond, that requires energy
347×2+154×3=1156KJ.
Then we form 4 S-F bonds, 2 HF bonds, that give out energy
4×327+2×565=2438KJ.
Therefore the reaction is δH=1238−2438=−1282KJ
No comments:
Post a Comment