Solution:
2a) f(g(x))=x if x≥0, otherwise f(g(x)) is undefined assuming the range of f and g are also real. If the ranges are complex then the f(g(x))=x for all real x.
2b) g(f(x))=|x| for all x∈R.
2c) g(f(−x))=|x| for all x∈R.
2d) No, they are not, even if the range is complex.
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