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Cecilia's Random Thoughts
Friday, October 23, 2015
Limit
Problem:
Solution:
x
n
−
a
n
x
−
a
=
(
x
−
a
)
(
x
n
−
1
+
a
x
n
−
2
+
.
.
+
a
n
−
1
)
x
−
a
=
(
x
n
−
1
+
a
x
n
−
2
+
.
.
+
a
n
−
1
)
Therefore
lim
x
→
a
x
n
−
a
n
x
−
a
=
lim
x
→
a
(
x
n
−
1
+
a
x
n
−
2
+
.
.
+
a
n
−
1
)
=
n
a
n
−
1
.
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