Problem:
Solution:
$ \cot(\theta - \frac{\pi}{2}) $
By definition of cotangent, we have
$ = \frac{\cos(\theta - \frac{\pi}{2})}{\sin(\theta - \frac{\pi}{2})} $
By phase shift formulas, we have
$ = \frac{\sin(\theta)}{-\cos(\theta)} $
By definition of tangent, we finally get
$ = -\tan(\theta) $
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