Soluability constant

Problem:



Solution:

By the chemical formula, for every cation, we have two anion.

$ [A^-] = 2.2 \times 10^{-4} \times 2 = 4.4 \times 10^{-4} $

Therefore the solubility product $ K_{sp} = [M^{+2}][A^{-1}] = 2.2 \times 10^{-4} \times 4.4 \times 10^{-4} = 9.68 \times 10^{-8} $